x^2+2ix-5=0

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Solution for x^2+2ix-5=0 equation:


Simplifying
x2 + 2ix + -5 = 0

Reorder the terms:
-5 + 2ix + x2 = 0

Solving
-5 + 2ix + x2 = 0

Solving for variable 'i'.

Move all terms containing i to the left, all other terms to the right.

Add '5' to each side of the equation.
-5 + 2ix + 5 + x2 = 0 + 5

Reorder the terms:
-5 + 5 + 2ix + x2 = 0 + 5

Combine like terms: -5 + 5 = 0
0 + 2ix + x2 = 0 + 5
2ix + x2 = 0 + 5

Combine like terms: 0 + 5 = 5
2ix + x2 = 5

Add '-1x2' to each side of the equation.
2ix + x2 + -1x2 = 5 + -1x2

Combine like terms: x2 + -1x2 = 0
2ix + 0 = 5 + -1x2
2ix = 5 + -1x2

Divide each side by '2x'.
i = 2.5x-1 + -0.5x

Simplifying
i = 2.5x-1 + -0.5x

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